3x^2+6x-672=0

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Solution for 3x^2+6x-672=0 equation:



3x^2+6x-672=0
a = 3; b = 6; c = -672;
Δ = b2-4ac
Δ = 62-4·3·(-672)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-90}{2*3}=\frac{-96}{6} =-16 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+90}{2*3}=\frac{84}{6} =14 $

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